Question

I am trying to get the sum(comprate) for only max(effdt) having max(id) from the following query,

SELECT  id, employee_code, effdt, comprate
FROM         dbo.employees_compensation
WHERE     (employee_code = '000321514')
ORDER BY effdt desc, id desc

Result of above query is as follows,

id      employee_code   effdt                   comprate
1473433 000321514       2010-09-02 00:00:00.000 46000
1473432 000321514       2010-09-02 00:00:00.000 138000
1453627 000321514       2010-09-02 00:00:00.000 46000
1453626 000321514       2010-09-02 00:00:00.000 138000
1447165 000321514       2010-09-02 00:00:00.000 46000
1447164 000321514       2010-09-02 00:00:00.000 138000
1424948 000321514       2010-09-02 00:00:00.000 46000
1424947 000321514       2010-09-02 00:00:00.000 138000
1405789 000321514       2010-09-02 00:00:00.000 46000
1405788 000321514       2010-09-02 00:00:00.000 138000

I tried many queries but I am not getting the expected result. What I want is the top first two values from above result i.e,

id    employee_code effdt                   comprate
1473433 000321514   2010-09-02 00:00:00.000 46000
1473432 000321514   2010-09-02 00:00:00.000 138000

and then get the sum(comprate) from the above result i.e,

sum(comprate)
184000

Could you help me in getting the expected result? Thanks in Advance.

Answer 1

How about the following?

SELECT     SUM(comprate) AS ComprateSum
FROM         (SELECT     TOP (2) id, employee_code, effdt, comprate
                       FROM          _Test
                       WHERE      (employee_code = '000321514')
                       ORDER BY effdt DESC, id DESC) AS derivedtbl_1