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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:11:19+00:00 2026-05-14T04:11:19+00:00

I am trying to get up to speed with Python, trying to replace some

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I am trying to get up to speed with Python, trying to replace some C with it. I have run into a problem with sharing data between modules, or more likely my understanding of the whole thing. I have a signal module which simplified is:

import sys, signal

sigterm_caught = False

def SignalHandler(signum, stackframe):
  if signum == signal.SIGTERM:
    sigterm_caught = True
    sys.stdout.write("SIGTERM caught\n")

def SignalSetup():
  signal.signal(signal.SIGTERM, SignalHandler)

and my main code has a loop like this:

signals.SignalSetup()
while signals.sigterm_caught == False:
  sys.stdout.write("sigterm_caught=%s\n" % str(signals.sigterm_caught))
  time.sleep(5)

I run it, then kill the process, inside signals.py it gets the signal, sets sigterm_caught to True, but the loop in the main process does not see a change in value of sigterm_caught.

So (a) is my approach completely wrong for the Python way?
(b) am I doing something wrong in trying to reference variables in the module?
and (c) should I be handling signals differently, like raising an exception?

Addition:
Is it better to handle signals by raising an exception, or is my old C approach still a valid one?

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:11:20+00:00Added an answer on May 14, 2026 at 4:11 am

    You need to add a global statement to the handler:

    def SignalHandler(signum, stackframe):
      global sigterm_caught
      if signum == signal.SIGTERM:
        sigterm_caught = True
        sys.stdout.write("SIGTERM caught\n")
    

    The Python compiler, by default, deems each name (like sigterm_caught) to be local to a function if it seems the function assign to the name; the role of the global statement is to reverse this default, so that the Python compiler will deem the name to be global (i.e., a module-level top name) instead.

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