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Home/ Questions/Q 8154077
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T16:13:34+00:00 2026-06-06T16:13:34+00:00

I am trying to grok the output of a function which doesn’t have the

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I am trying to grok the output of a function which doesn’t have the courtesy of setting a result code. I can tell it failed by the “error:” string which is mixed into the stderr stream, often in the middle of a different conversion status message.

I have the following list comprehension which works, but scans for the “error:” string twice. Since it is only rescanning the actual error lines, it works fine, but it annoys me I can’t figure out how to use a single scan. Here’s the working code:

errors = [e[e.find('error:'):] for e in err.splitlines() if 'error:' in e]

The obvious (and wrong) way to simplify is to save the “find” result

errors = [e[i:] for i in e.find('error:') if i != -1 for e in err.splitlines()]

However, I get “UnboundLocalError: local variable ‘e’ referenced before assignment”. Blindly reversing the ‘for’s in the comprehension also fails. How is this done?

THanks. Kent

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  1. Editorial Team
    Editorial Team
    2026-06-06T16:13:37+00:00Added an answer on June 6, 2026 at 4:13 pm

    You can place the check for 'error' inside a generator expression:

    [e[i:] for i,e in
     ((e.find('error:'),e) for e in err.splitlines())
     if i != -1]
    

    What you did was to create a nested comprehension and, by using the e variable before the second loop, you got the UnboundLocalError

    BTW, you can also use regex and avoid this comprehension:

    re.findall('error:(.*)', err)
    

    No need to split lines also.

    for the complete error (with the error: part) this works:

    re.findall('error:.*', err)
    
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