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Editorial Team
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Asked: 2026-05-26T04:09:45+00:00

I am trying to have 2 separate divs with one labeled Email and the

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I am trying to have 2 separate divs with one labeled Email and the 2nd div named Number. When a user chooses a person from drop down the retrieved info from PHP + MySQL should be added in a div just how it gets added to the div when you click add at: http://jsfiddle.net/QVUHU/84/

I am stuck because I dont know how to add the retrieved info into 2 divs one for email one for number like the one at js fiddle…

Below is my html + ajax and PHP code

HTML + AJAX

<html>
<head>
<script type="text/javascript">
function showUser(str)
{
if (str=="")
  {
  document.getElementById("txtHint").innerHTML="";
  return;
  }
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("txtHint").innerHTML+=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>

<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="1">Achau</option>
<option value="2">Ravi</option>
<option value="3">Justin</option>
</select>
</form>
<br />


<div id="txtHint">
<b><table>
<tr>
<th>Email</th>
<th>Number</th>

</tr></b></div>



</body>
</html>

PHP + MySQL

<?php
$q=$_GET["q"];

$con = mysql_connect("tghbdfg1","Userbhgins","Jpgbhfw3");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("UserLogins", $con);

$sql="SELECT * FROM PersonInfo WHERE id = '".$q."'";

$result = mysql_query($sql);

echo " <br />";

while($row = mysql_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>" . $row['Email'] . "</td>";
  echo "<td>" . $row['PNumber'] . "</td>";
  echo "</tr>";
  }
echo "</table>";

mysql_close($con);
?>
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1 Answer

  1. Editorial Team

    HTML: 

    <th>Email: <div id="email"></div></th>
<th>Number: <div id="number"></div></th>

    JavaScript:

    document.getElementById["email"].innerHTML = "Hello";
document.getElementById["number"].innerHTML = "World";

    EDIT:

    No need to return html tags in your respnse. There are better ways to do this(JSON response) but this is simplest solution:

    while($row = mysql_fetch_array($result))
  {
  echo $row['Email'] . "|" . $row['PNumber'];
  }

    Javascript:

    Replace

    document.getElementById("txtHint").innerHTML+=xmlhttp.responseText;

    With:

    var emailPhoneArray = xmlhttp.responseText.split("|");

if(emailPhoneArray != null && emailPhoneArray.length() == 2) {
    document.getElementById["email"].innerHTML = emailPhoneArray[0];
    document.getElementById["number"].innerHTML = emailPhoneArray[1];
}
else {
    alert("Wrong response!");
}
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