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Home/ Questions/Q 6177501
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T00:17:15+00:00 2026-05-24T00:17:15+00:00

I am trying to have some kind of dynamically growing array/data structure in C.

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I am trying to have some kind of dynamically growing array/data structure in C. Below is the C code I have for it. But after it prints the array, it gives a run-time error as shown below in the snapshot. What is going wrong? It is being compiled using MS-Visual C++ 2010 (Free version) on a Windows-7.

enter image description here

#include <stdio.h>
#include <stdlib.h>

int main(void) {
 int *a;
 int i = 5;

 if((a = (int *)malloc(i * sizeof(int))) == NULL) {
  fprintf(stderr, "Error: failed malloc\n");
  return 1;
 }
 for(i = 0; i < 5; i++) 
  a[i] = i;

 printf("-- array after malloc\n");
 for(i = 0; i < 5; i++) 
  printf(" a[%d] = %d\n", i, a[i]);

 if((a = (int *)realloc(a, i * sizeof(int))) == NULL) {
  fprintf(stderr, "Error: failed realloc\n");
  return 1;
 }
 for(i = 0; i < 10; i++) 
  a[i] = i;


 printf("\n-- array after realloc\n");
 for(i = 0; i < 10; i++) 
  printf(" a[%d] = %d\n", i, a[i]);


 free(a);
 return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T00:17:16+00:00Added an answer on May 24, 2026 at 12:17 am
    //<important> 
    //weren't you supposed to do i = 10 here ????
    //</important>
    if((a = (int *)realloc(a, i * sizeof(int))) == NULL) {
      fprintf(stderr, "Error: failed realloc\n");
      return 1;
     }
     for(i = 0; i < 10; i++) 
      a[i] = i;
    

    I think this was supposed to resize array to 10 and use it, but you never changed i to 10 so i is still 5 and you go out of range

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