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Editorial Team
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Asked: 2026-06-10T16:02:43+00:00

I am trying to identify the consecutive three-column groups that have >2 instances of

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I am trying to identify the consecutive three-column groups that have >2 instances of “1” in this matrix.

A=[1 2 3 4 5 6 7 8 9 10 11 0 0 0 0 0 0;
   0 1 2 3 4 5 6 7 8 9 10 11 0 0 0 0 0;
   0 0 0 0 1 2 3 4 5 6 7 8 9 10 11 0 0;
   1 2 3 4 5 6 7 8 9 10 11 0 0 0 0 0 0;
   0 0 1 2 3 4 5 6 7 8 9 10 11 0 0 0 0;
   0 0 0 0 1 2 3 4 5 6 7 8 9 10 11 0 0]

Can anyone help?

For example, columns 1-3 have 4 instances of “1” (which is >2); columns 2-4 have only 2 instances of “1” (not >2); columns 3-5 have 3 instances of “1” (>2). None of the remaining three-column groups have >2 instances of “1”. So the desired results would be

[1 0 1 0 0 0 0 0 ... ]
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1 Answer

  1. Editorial Team

    A one line solution:

    A=[1 2 3 4 5 6 7 8 9 10 11 0 0 0 0 0 0;
   0 1 2 3 4 5 6 7 8 9 10 11 0 0 0 0 0;
   0 0 0 0 1 2 3 4 5 6 7 8 9 10 11 0 0;
   1 2 3 4 5 6 7 8 9 10 11 0 0 0 0 0 0;
   0 0 1 2 3 4 5 6 7 8 9 10 11 0 0 0 0;
   0 0 0 0 1 2 3 4 5 6 7 8 9 10 11 0 0];

found = conv(sum(A ==1), [1 1 1], 'valid') > 2

    Result:

    found =

     1     0     1     0     0     0     0     0     0     0     0     0     0     0     0
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