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Home/ Questions/Q 7075725
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T06:12:42+00:00 2026-05-28T06:12:42+00:00

I am trying to implement a function to change state of the menu, but

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I am trying to implement a function to change state of the menu, but my reference is lost when it leaves the function:

void gotoLowerlevel(Menu *item)
{
    if (item->chld != 0x00) {
        item = item->chld;
    }
}

The function call is done in this manner (currentState is a pointer to struct Menu):

case ENTER:
    if (cnsle->inMenuFlag == 0)
    {
        cnsle->inMenuFlag = 1;
        cnsle->currentState = cnsle->root;
        gotoLowerlevel(cnsle->currentState);
        displayMenu(cnsle->currentState,&cnsle->display);
    }

I have no idea why this isn’t working. Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T06:12:43+00:00Added an answer on May 28, 2026 at 6:12 am

    item in gotoLowerLevel is a local variable even if it is a reference to an object elsewhere. To modify cnsle->currentState you need to either:

    • pass in cnsle
    • pass in a reference to cnsle->currentState (that is change the method signature to Menu ** itemptr and the call parameter to &cnsle->currentState)
    • or return the new value from gotoLowerLevel and assign it: cnsle->currentState = gotoLowerLevel(cnsle->currentState)

    My preference would be the last option, as this makes it clear when reading the calling code that currentState may be modified.

    Others have explained how to pass a reference. Code for my preferred solutions is:

    Menu* gotoLowerlevel(Menu *item)
    {
        if (item->chld != 0x00) {
            item = item->chld;
        }
        return item;
    }
    
    /* .... */
    cnsle->currentState = gotoLowerlevel(cnsle->currentState);
    
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