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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T18:07:45+00:00 2026-05-11T18:07:45+00:00

I am trying to implement a template class that would be able to tell

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I am trying to implement a template class that would be able to tell me if a variable is a class,structure or a basic type.

So far I’ve come with this:

template< typename T >
class is_class
{
private:
    template< typename X >
    static char ( &i_class( void(X::*)() ) )[1];
    //
    template< typename X >
    static char ( &i_class( X ) )[2];
public:
    static bool const val = sizeof( i_class< T >(0) ) == 1;
};

and ussage:

is_class< int >::val; // false
is_class< some_class_type >::val; // true

The problem is that now I need to write a blank void function in every class that could be used with this code.

Does anyone know a solution to this problem?

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  1. Editorial Team
    Editorial Team
    2026-05-11T18:07:45+00:00Added an answer on May 11, 2026 at 6:07 pm

    is_class is a member of the Boost.Type_Traits library. The implementation is probably similar to what you already have. You would use in in conjunction with enable_if to create the function if appropriate:

    template <class T>
       typename enable_if_c<boost::is_class<T>::value>::type 
         foo() {  }
    

    Or the equivalent:

    template <class T>
       typename enable_if<boost::is_class<T>>::type 
         foo() {  }
    

    The function foo is only generated if the type T is of class type.

    The return value for the function, if it is generated, is the second parameter (omitted) to the enable_if template (the default is void).

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