Question

I am trying to insert a date in my Database which I get from a php input.
The code I am using to insert the value looks like this

$length = strrpos($fristdatum, " ");
$newDate = explode(".", substr($fristdatum, $length));
$fristdatum = $newDate[2] . "-" . $newDate[1] . "-" . $newDate[0];

Lets say I enter 14.12.2012 as the date if I echo $fristdatum I get 2012-12-14 but as soon as I insert it in my MySQL DB it turn to 2014.12.20 any ideas?

The Column Type is date. The insert is somewhat like this

mysql_query("INSERT INTO sch_anschreiben (date)values('$fristdatum'))

there are more values but I guess that doesn’t matter

Thanks in Advance!

Well thanks for the help guys i figured it out i used $fristdatum in a array for str_replace ,after i formated it, like this

$patern = array("[Date]")
$words=array($fristdatum)
$content = str_replace($patern, $words, $content);

and after that inserted it in the DB now I changed it so it would format after the str_replace and it seems to work just fine.
also would appreciate if someone could explain me why^^.

Answer 1

Instead of explode and hard coded conversion, prefere using DateTime::createFromFormat if you have PHP 5.3 or later.

$date = DateTime::createFromFormat('d. m. Y',$fristdatum);
echo $date->format('Y-m-d');//echoes 2012-12-14

Now that you correct your script to register your dates the right way, you should ensure your database is good.
You can use this request I think :

UPDATE yourtable SET yourdate=CONCAT(MONTH(yourdate),'-',DAY(yourdate),'-',YEAR(yourdate)) WHERE MONTH(yourdate) > 12