Question

I am trying to insert data in table in mysql database through php code but I am always getting following error:
Invalid query: Table ‘whatsup_wp1.pushDevices’ doesn’t exist

I am using following code:

    <?php 
    $deviceid = $_GET["deviceid"];
    $link = mysql_connect('localhost', 'whatsup_wp1', 'XSvUCl0FugzV4');
    if (!$link) {
        die('Not connected : ' . mysql_error());
    }

    // make foo the current db
    $db_selected = mysql_select_db('whatsup_wp1', $link);
    if (!$db_selected) {
        echo 'Can\'t use whatsup_wp1 : ' . mysql_error();
    }
    else
        {
    //echo 'connect';
    }
    //$query = "select count(*) from city";
    //$query = "insert into devices (pushID) values('".$deviceid."')";
    $query = "INSERT INTO pushDevices(device) VALUES ('".$deviceid."')";
    echo $query;
    $result = mysql_query($query);
    if (!$result){
        die('Invalid query: ' . mysql_error());
    }
    echo $result;
    ?>

This database have more tables and I am able to use them. I am having problem with the tables that I am creating today. They appears in phpmyadmin but somehow I am not able to get use them through my php code.

Any help may be vital for me. I have spent complete day on it.

Thanks
Pankaj

Answer 1

Its hard to tell by What your saying but i have a suggestion…. It looks like theres no table selected try this

it formatted like this

$query = "INSERT INTO mydb.mytable
(mytablefield)
VALUES
('myfieldvalue')"
$result = mysql_query($query);
if (!$result){
    die('Invalid query: ' . mysql_error());
}

My guess is you meant for it to be like this?

$query = "INSERT INTO whatsup_wp1.devices 
(device)
VALUES
('".$deviceid."')"
$result = mysql_query($query);
if (!$result){
    die('Invalid query: ' . mysql_error());
}

And for security reasons i recommend this…

else
    {
//echo 'connect';
$deviceid = mysql_real_escape_string(stripslashes($deviceid));
}

Change to

else
    {
//echo 'connect';
$deviceid = mysql_real_escape_string(stripslashes($deviceid));
}

Personally i just use it like this

$result = mysql_query("INSERT INTO mytable
(mytablefield)
VALUES
('myfieldvalue')");
if($result){echo "Works!";}
else{die('Invalid query: ' . mysql_error());exit();}