Question

I am trying to integrate the following blog APP https://github.com/nathanborror/django-basic-apps ,so in my main urls.py i have included the blog urls as (r'^blog/',include('basic.blog.urls')), Now my question is that now when i point my browser to the blog APP http://127.0.0.1/blog/ i get a message as “Post archive”,How to proceed from here i.e, how to post blog and retrieve the same.What is the url to be used..The following is the blog urls

from django.conf.urls.defaults import *


urlpatterns = patterns('basic.blog.views',
url(r'^(?P<year>\d{4})/(?P<month>\w{3})/(?P<day>\d{1,2})/(?P<slug>[-\w]+)/$',
    view='post_detail',
    name='blog_detail'
),
url(r'^(?P<year>\d{4})/(?P<month>\w{3})/(?P<day>\d{1,2})/$',
    view='post_archive_day',
    name='blog_archive_day'
),
url(r'^(?P<year>\d{4})/(?P<month>\w{3})/$',
    view='post_archive_month',
    name='blog_archive_month'
),
url(r'^(?P<year>\d{4})/$',
    view='post_archive_year',
    name='blog_archive_year'
),
url(r'^categories/(?P<slug>[-\w]+)/$',
    view='category_detail',
    name='blog_category_detail'
),
url (r'^categories/$',
    view='category_list',
    name='blog_category_list'
),
url(r'^tags/(?P<slug>[-\w]+)/$',
    view='tag_detail',
    name='blog_tag_detail'
),
url (r'^search/$',
    view='search',
    name='blog_search'
),
url(r'^page/(?P<page>\d+)/$',
    view='post_list',
    name='blog_index_paginated'
),
url(r'^$',
    view='post_list',
   name='blog_index'
),
)

Answer 1

There are no URLs specific to post creation, so you need to do it via the Admin interface. I looked at the code and there is a specific template for creating/modifying post objects.