Question

I am trying to iterate through a MySQL object and use an ajax call on another page to append the data but I can’t get the php to return valid JSON to the callback.

This one obviously doesn’t work…

<?php

    $db_host = "localhost";
    $db_user = "blah";
    $db_pass = "blah";
    $db_name = "chat";
    $mysqli = new MySQLi($db_host, $db_user, $db_pass, $db_name);
    $myQuery = "SELECT * FROM users";
    $result = $mysqli->query($myQuery) or die($mysqli->error);
    $row = $result->fetch_assoc();
    echo json_encode($row);

?>

Or this one…

<?php

    $db_host = "localhost";
    $db_user = "blah";
    $db_pass = "blah";
    $db_name = "chat";
    $mysqli = new MySQLi($db_host, $db_user, $db_pass, $db_name);
    $myQuery = "SELECT * FROM users";
    $result = $mysqli->query($myQuery) or die($mysqli->error);
    while ( $row = $result->fetch_assoc() ){
        echo json_encode($row) . ", ";
    }

?>

Answer 1

$data = array();

while ( $row = $result->fetch_assoc() ){
    $data[] = json_encode($row);
}
echo json_encode( $data );

This should do it. Also, you can use http://jsonlint.com/ to see what are the problems with your JSON output.

Update: using fetch_all() might be a good idea too

$data = $result->fetch_all( MYSQLI_ASSOC );
echo json_encode( $data );