Question

I am trying to join a select disinct statement to a select sum statement. Here is an example of the data

CD  STDATE    ENDDATE   PR F1  01/02/09  01/04/09  $10 F1  01/02/09  01/04/09  $40 F1  01/02/09  01/04/09  $20 F1  01/02/09  01/04/09  $30 F1  01/22/09  01/26/09  $10 F1  01/22/09  01/26/09  $50 F1  01/22/09  01/26/09  $20 

My desired output is –

F1  01/02/09  01/04/09  $100 F1  01/22/09  01/26/09  $80 

So far, I have the foll statement, which is incorrect:

SELECT DISTINCT STDATE, ENDDATE, CD FROM TABLE AS A  INNER JOIN (SELECT SUM(PR) FROM TABLE) AS B  ON A.STDATE=B.STDATE 

How can I do that???

Answer 1

I think you are looking for grouping:

select     t.cd,     t.stdate,     t.enddate,     sum(t.pr) from     table t group by     t.cd,     t.stdate,     t.enddate