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Home/ Questions/Q 6973091
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T17:03:49+00:00 2026-05-27T17:03:49+00:00

i am trying to Json parsing in my android app the link is https://www.buzzador.com/apps/present_software/webservice/index.php?op=ProductQ&campaign_id=607&userid=10776

  • 0

i am trying to Json parsing in my android app the link is https://www.buzzador.com/apps/present_software/webservice/index.php?op=ProductQ&campaign_id=607&userid=10776

when i put it into Json object it gives errors to me
error is :
08-31 14:40:52.281: WARN/System.err(416): org.json.JSONException: Value of type java.lang.String cannot be converted to JSONObject

public static String getmyproductquestiondetails(String userid,
        String campaignid) {// https://www.buzzador.com/apps/present_software/webservice/index.php?op=EducationResult&userid=1&questionid=1,2,3&answergivenbyuser=1,1,0
    String data = null;
    try {

        URL url = new URL(
                "http://dignizant.com/buzz/webservice/index.php?op=getProductQuestion&userid="
                        + userid + "&campaign_id=" + campaignid);
        if (url.getProtocol().toLowerCase().equals("https")) {
            trustAllHosts();
            HttpsURLConnection https = (HttpsURLConnection) url
                    .openConnection();
            https.setHostnameVerifier(DO_NOT_VERIFY);
            http = https;
        } else {
            http = (HttpURLConnection) url.openConnection();
        }
    } catch (MalformedURLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    Utils utils = new Utils();

    try {
        data = utils.convertStreamToString(http.getInputStream());
        System.out.println("getproduct details response :: " + data);

    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();

        data = e.toString();

    }
    return data;
}







try {


        JSONObject jo = new JSONObject(response);

    } catch (Exception e) {
        // TODO: handle exception
        e.printStackTrace();
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T17:03:50+00:00Added an answer on May 27, 2026 at 5:03 pm
      char[] utf8 = null;
                StringBuilder properString = new StringBuilder("");
    
                utf8 = Response.toCharArray();
    
                for (int i = 0; i < utf8.length; i++) {
                    if ((int) utf8[i] < 65000) {
                        properString.append(utf8[i]);
                    }
                }
      System.out.println("Response of Login::"
                            + properString.toString());
    
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