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Home/ Questions/Q 9135297
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T08:48:21+00:00 2026-06-17T08:48:21+00:00

I am trying to learn more about Method chaining in Javascript and would like

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I am trying to learn more about Method chaining in Javascript and would like to know the proper way to create a delay with no jQuery to the next function in the chain:

var foo = function() {
    this.delay = function(per) {
        setTimeout(start, per);
        return this;
    };
    this.start = function() {
        alert('start!');
    };
};

var bar = new foo().delay(1000).start();
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  1. Editorial Team
    Editorial Team
    2026-06-17T08:48:21+00:00Added an answer on June 17, 2026 at 8:48 am

    This isn’t easy to do. jQuery uses a specific queue system.

    Suppose you want to do it without jQuery, you would have to implement a queue yourself.

    For example this very simplistic implementation :

    var foo = function() {
        var queue = [];
        var timer;
        this.delay = function(per) {
          timer = setTimeout(function(){
            timer = 0;
            var f;
            while (f = queue.shift()) f();
          }, per);
          return this;
        };
        this.addFunction = function(f) {
          if (timer) queue.push(f);
          else f();
          return this;
        };
        this.start = function() {
           this.addFunction(function(){alert('start')});
           return this;
        };
    };
    

    Demonstration


    If you want to chain another function not defined in foo, you may do

    var bar = new foo().delay(3000).start()
        .addFunction(function(){alert("another chained one")});
    

    Demonstration

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