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Home/ Questions/Q 6784097
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:56:55+00:00 2026-05-26T16:56:55+00:00

I am trying to learn perl programming and am using it to read a

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I am trying to learn perl programming and am using it to read a file from a contest;

#!/usr/local/bin/perl
use warnings;

open(FILE, <~/source/test.txt>);
@array = <FILE>;
$number = shift @array;

while($number--) {
    chomp($key = shift @array);
    chomp($message = shift @array);

    print "Key: $key";
    print "Message: $message";
}
print "\n";
close(FILE);

The file contains a number, N, then there are 2 * N lines that follow which is how many key/message pair’s there are.

But when I do this program, it only prints out the last “message” and nothing else… it doesn’t print anything else. If I remove the chomps it works as intended, but with the chomps there it just cuts everything off… any ideas why?

//EDIT: removed the -w

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:56:55+00:00Added an answer on May 26, 2026 at 4:56 pm

    You are reading a DOS/Win text file on a unix box. Using chomp, you are removing the “LF” of “CRLF”, but leaving the “CR”, causing all your lines to be shown one atop the other.

    #!/usr/local/bin/perl -w
    use strict;   # Do use this!
    use warnings;
    
    open(my $fh, '<', "$ENV{HOME}/source/test.txt") or die $!;
    my @array = <$fh>;
    s/\s+\z// for @array;  # Universal chomp
    
    my $number = shift(@array);
    while ($number--) {
       my $key     = shift(@array);
       my $message = shift(@array);
    
       print "Key: $key\n";
       print "Message: $message\n";
    }
    
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