Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4347314
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 21, 20262026-05-21T12:17:23+00:00 2026-05-21T12:17:23+00:00

I am trying to limit the last left join to only 1 result $query=SELECT

  • 0

I am trying to limit the last left join to only 1 result

$query="SELECT a.*, cc.name AS category, ee.ezcity AS proploc
       , dd.name AS statename, bb.name AS countryname
       , u.logo_image AS logo_image, u.mid AS mid
       , u.dealer_name AS dealer_name, u.dealer_company AS dealer_company
       , u.dealer_phone AS dealer_phone, u.dealer_mobile AS dealer_mobile
       , u.published AS dealerpublished, sp.tenant AS tenant
       , sp.spacenum AS spacenum, sp.sf AS sf, sp.image AS tenantimage
       , u.dealer_type AS dealer_type 
     FROM #__ezrealty as a"
    . "\n LEFT JOIN #__ezrealty_catg AS cc ON cc.id = a.cid"
    . "\n LEFT JOIN #__ezrealty_locality AS ee ON ee.id = a.locid"
    . "\n LEFT JOIN #__ezrealty_state AS dd ON dd.id = a.stid"
    . "\n LEFT JOIN #__ezrealty_country AS bb ON bb.id = a.cnid"
    . "\n LEFT JOIN #__ezrealty_profile AS u ON u.mid = a.owner"
    . "\n LEFT JOIN #__ezrealty_siteplan AS sp ON sp.listing_id = a.id "
    . "\n WHERE $extrastring AND a.published = '1' $vacant 
          AND cc.access <= $my->gid $wheres "
    . $order.' LIMIT '.$pageNav->limitstart.', '.$pageNav->limit;

I have tried :

. "\n  LEFT JOIN (SELECT listing_id FROM #__ezrealty_siteplan LIMIT 1) sp 
         ON sp.listing_id = a.id"
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-21T12:17:24+00:00Added an answer on May 21, 2026 at 12:17 pm

    I think your result look like it contains more than 1 because the results are not GROUP BY any column.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Trying to make a make generic select control that I can dynamically add elements
Trying to setup an SSH server on Windows Server 2003. What are some good
Trying to get my css / C# functions to look like this: body {
Trying to find some simple SQL Server PIVOT examples. Most of the examples that
Trying to keep all the presentation stuff in the xhtml on this project and
Trying to make a MySQL-based application support MS SQL, I ran into the following
Trying to create a QtRuby application, I get the following error: /usr/lib64/ruby/site_ruby/1.8/Qt/qtruby4.rb:2144: [BUG] Segmentation
Trying to do this sort of thing... WHERE username LIKE '%$str%' ...but using bound
Trying to perform a single boolean NOT operation, it appears that under MS SQL
Trying to honor a feature request from our customers, I'd like that my application,

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.