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Home/ Questions/Q 7489931
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T15:24:31+00:00 2026-05-29T15:24:31+00:00

I am trying to list all the duplicate records in a table. This table

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I am trying to list all the duplicate records in a table. This table does not have a Primary Key and has been specifically created only for creating a report to list out duplicates. It comprises of both unique and duplicate values.

The query I have so far is:

SELECT [OfficeCD]

      ,[NewID]
      ,[Year]
      ,[Type]
  FROM [Test].[dbo].[Duplicates]

  GROUP BY [OfficeCD]

       ,[NewID]
      ,[Year]
      ,[Type]
      HAVING COUNT(*) > 1

This works right and gives me all the duplicates – that is the number of times it occurs.

But I want to display all the values in my report of all the columns. How can I do that without querying for each record separately?

For example:

Each table has 10 fields and [NewID] is the field which is occuring multiple times.I need to create a report with all the data in all the fields where newID has been duplicated.

Please help.
Thank you.

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  1. Editorial Team
    Editorial Team
    2026-05-29T15:24:33+00:00Added an answer on May 29, 2026 at 3:24 pm

    You need a subquery:

    SELECT * FROM yourtable 
    WHERE NewID IN (
      SELECT NewID FROM yourtable
      GROUP BY OfficeCD,NewID,Year,Type
      HAVING Count(*)>1
    )
    

    Additionally you might want to check your tags: You tagged mysql, but the Syntax lets me think you mean sql-server

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