Question

I am trying to list out all records from a database that have not expired.

i have a jobs listing site being developed, i have code to grab all the ‘active’ job details from the database and list out.

$mysql = new mysqli(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME) or die('There was a problem connecting to the database');
$stmtJ = $mysql->prepare('SELECT id,jobtitle,vcref,jobtype,jobintro,closingdate FROM jobs WHERE active = 1');

$stmtJ->execute();
$stmtJ->store_result();
$stmtJ->bind_result($id,$jobtitle,$vcref,$jobtype,$jobintro,$closingdate);
$totalLiveJobs = $stmtJ->num_rows();

and is outputted like so:

<?php
while($row = $stmtJ->fetch()) :
echo("<p>job detail here</p>");
endwhile; 
?>

and i also have an ‘if statement’ snippet to see if the job has expired or not (i.e if expires {expires is a date yyyy-mm-dd} is greater than ‘$now’ it should not show up.

$expires = date('Y-m-d-H-i-s',strtotime("$closingdate 12:00:00"));

$now = date('Y-m-d-H-i-s');


if ($expires < $now) {

echo ("<h3>Live Jobs Here</h3> $expires");

} else {

echo ("<h3>Job Expired</h3> $now");

}

However, i’m having problems merging the two together with the main goal being all jobs that have not yet expired will be shown on the page, any jobs that have expired should not be shown on the page.

I am pulling my hair out here, any help welcome, any requests for further details i’ll respond as soon as i possibly can.

thx in advance

Answer 1

depending on your database structure, you could do

SELECT * FROM jobs WHERE active = 1 AND closingdate >= NOW()