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Home/ Questions/Q 8398221
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T20:59:32+00:00 2026-06-09T20:59:32+00:00

I am trying to loop an array of integers using pointer, but I get

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I am trying to loop an array of integers using pointer, but I get a strange values..

int nums[1] = { 1 };
int *p = nums;
while(*p != NULL) {
    cout << " LOOPING, p is " << *p << endl;
    p++;
}

When I am running, I am getting the next output:

 LOOPING, p is 1
 LOOPING, p is -858993460
 LOOPING, p is 4454504
 LOOPING, p is 3032019

Why I am get those strange values? I should see only “1”, because I am looping until I get NULL pointer, and on each loop I move the next pointer.

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  1. Editorial Team
    Editorial Team
    2026-06-09T20:59:34+00:00Added an answer on June 9, 2026 at 8:59 pm
    while(*p != NULL) {
    

    The comparison is wrong for 2 reasons:

    • *p is an integer, not a pointer like NULL implies
    • the array isn’t 0 terminated, so even if NULL is treated like a fancy 0, it won’t work

    You could try:

    int nums[] = {1, 0};
    while(*p)
    
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