Question

I am trying to make a confirm box which will desire which php code will be executed.
Heres my code:

<script type="text/javascript">
    var answer = confirm('Are you sure?');

    if(answer==true)
       {
          <?php $confirmation = 1; ?>
       } 
    else 
       { 
          <?php define("CONFIRMATION", 1, true); ?>
       }
         alert('<?php echo $confirmation; ?>')
         alert('<?php echo defined("CONFIRMATION"); ?>')
</script>

The problem is , even if i click YES, $confirmation and boolean from defined() function returns 1.
Whatever I click, (cancel or ok) one of them should be 0 (I’ve already declared $confirmation before)
But both of codes at if and else blocks are used!
Normally it works like this

Answer 1

You fundamentally misunderstand what PHP is doing.

PHP is evaluated on the server before the page is sent to your browser. By the time the browser sees it and executes the javascript, all the PHP is gone.

Use your browser’s “view source” on the browser window with this code in it. You’ll see it looks like this:

<script type="text/javascript">
var answer = confirm('Are you sure?');

if(answer==true)
   {
             } 
else 
   { 
             }
     alert('1')
     alert('1')
</script>

You either need to implement what you want to do in javascript to run on the browser, or you need to send a new request to the server and get a new page back (either directly or indirectly) with your response.