Question

I am trying to make a login script where for database connection I am using PDO MYSQL. Here is my code:

$query = "SELECT uid,uname  from user where email_address='[e-mail]' AND password='".md5('abcacb')."'";
    try {
        $dbh = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME,DB_USER,DB_PASS);
        $stmt = $dbh->query($query);
        $result = $stmt->fetch(PDO::FETCH_ASSOC);
        if(!$result)
            $status = FALSE;
        else
            $status = TRUE;
        $dbh = null;
    }
    catch(PDOException $e){
        echo $e->getMessage();
    }
    print $status;

When email_address & password both are correct $status is printing 1. But if email_address or password mismatch from the database value it’s not printing anything for $status. I assume that at least it should print 0. But I am not getting where I am wrong?

Answer 1

When email_address & password both are correct $status is printing 1.
But if email_address or password is mismatch from database value it’s
not printing any thing for $status

since you are sotring the boolean values in $status variable. boolean values have it’s own behavior in PHP.

boolean value true will always print `1`
boolean value false will print nothing.

try this

echo true;
//prints 1

echo false;
//prints nothing

if you want 0 to be printed, then you can do it like this.

$status = ($result == true) ? 1 : 0; 

above code is the ternary operator if you not aware. which is same as

if($result)
    $status = 1;
else
    $status = 0;

while using conditional statement, 1 will always be treated as boolean true and 0 as false.

i hope this answer your question.