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Editorial Team
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Asked: 2026-06-07T14:01:38+00:00

I am trying to make a php calendar, as part of a project, and

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I am trying to make a php calendar, as part of a project, and here I am executing some SQL with php:

mysql_select_db("waycov_dtm", $con);

$data="'Placeholder Text'";

$sql="INSERT INTO waycov_dtm.calDates (dateID, day, month, year)
VALUES (" . $dateID . ", " . $day . ", " . $month . ", " . $year . ");
INSERT INTO waycov_dtm.calData (dateID, data, memberID)
VALUES (" . $dateID . ", " . $data . ", 1);";

echo $sql;

if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }
echo "1 record added";

mysql_close($con);

When this executes, I get the following (the echoed sql and then the error):

INSERT INTO waycov_dtm.calDates (dateID, day, month, year) VALUES (7072012, 7, 07, 2012); INSERT INTO waycov_dtm.calData (dateID, data, memberID) VALUES (7072012, 'Placeholder Text', 1);Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO waycov_dtm.calData (dateID, data, memberID) VALUES (7072012, 'Placeh' at line 3

If i take out any one insert statment, the other runs, but both together causes this??

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1 Answer

  1. Editorial Team

    Use it like this:

    $sql="INSERT INTO waycov_dtm.calDates (dateID, day, month, year)
VALUES (" . $dateID . ", " . $day . ", " . $month . ", " . $year . ")";
$sql_second = "INSERT INTO waycov_dtm.calData (dateID, data, memberID)
VALUES (" . $dateID . ", " . $data . ", 1);";

if (!mysql_query($sql,$con) || !mysql_query($sql_second,$con))
{
  die('Error: ' . mysql_error());
}

    From the manual:

    mysql_query() sends a unique query (multiple queries are not
    supported)

    The use of mysql_query is discouraged. Use MySQLi or PDO.

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