Question

I am trying to make a table via PHP, but when I load this, it displays it like this..

The code:

<table border="1" cellpadding="5">
<?php
while($test= mysql_fetch_assoc($countquery)){
        echo '<tr><td>';
    echo $test["count"];
    echo 'x</td>';
};
while($row=mysql_fetch_array($topresult)) {
    echo '<td width="150">';
    echo $row["productnaam"];
    echo '</td><td width="100" style="text-align:center;">&euro; ';
    echo $row["prijs"];
    echo '</td><td width="50" style="text-align:center;">';
    echo '<a style="text-decoration:none;color:red;" href="#"><img width="25" src="trash.png"></a>';
    echo '</td></tr>';
};
?>
</table>

My goal is to display a table of 4 columns by 3 rows..

EDIT:
Found it already, it makes a new <tr> tag everytime the first while is performed.

Answer 1

The block :

while($test= mysql_fetch_assoc($countquery)){
        echo '<tr><td>';
    echo $test["count"];
    echo 'x</td>';
};

will create 3 cells 1x, 1x, 2x first,
next the block:

 while($row=mysql_fetch_array($topresult)) {
    echo '<td width="150">';
    echo $row["productnaam"];
    echo '</td><td width="100" style="text-align:center;">&euro; ';
    echo $row["prijs"];
    echo '</td><td width="50" style="text-align:center;">';
    echo '<a style="text-decoration:none;color:red;" href="#"><img width="25" src="trash.png"></a>';
    echo '</td></tr>';
};

will create cells from Monitor, so the result become like this.
To fix it, you should save the result from the first while loop to an array and go through at the 2nd while loop