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Home/ Questions/Q 8027997
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T23:59:22+00:00 2026-06-04T23:59:22+00:00

I am trying to make an Ajax call using JQuery to a servlet that

  • 0

I am trying to make an Ajax call using JQuery to a servlet that returns a JSON object.
In the JSP page I have a form, at first I didn’t know how the get the data from the form,
then I found .serialize.

I have the following JavaScript:

$(document).ready(function() {
    $("#submit").click(function blabla() {
        var formData = $('form').serialize();
        $.ajax({
            type: "POST",
            url: "/ArchiveSearch/Search",
            dataType: "json",
            data: formData,
        });
    });
});

The information comes from the following form:

<form method= post">
            <div class="searchCiteria">
                <div id="searchValueBlock1">
                        <div><span class="label">Case ID:</span><input type="text" name="messagecaseid"  size="25"/></div>
                        <div><span class="label">Onderwerp:</span><input type="text" name="messagesubject" size="25" /></div>
                        <div><span class="label">Afzender:</span><input type="text" name="messagesender"  size="25"/></div>
                        <div><span class="label">Ontvanger:</span><input type="text" name="messagereceiver"  size="25"/></div>
                </div>

                <div id= "searchValueBlock2">
                    <div><span class="label">Datum:</span><input type="text" name="date1"  size="25"/></div>
                    <div><span class="label"></span><input type="text" name="date2"  size="25"/></div>

                    <div class="submit">
                        <input type="submit" value="Search"> 
                    </div>
                </div>
            </div>
            </form>

When I use the action parameter in the form the servlet repondes like it should.
But I can’t seem to get the Ajax call to work.

What am I doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T23:59:23+00:00Added an answer on June 4, 2026 at 11:59 pm

    you must add the success param to ajax function

    $.ajax({
                type: "POST",
                url: "/ArchiveSearch/Search",
                dataType: "json",
                data: formData,
     success: function(data) {
        $('.result').html(data);
        alert('Load was performed.');
      }
    });

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