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Home/ Questions/Q 8669543
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T18:29:58+00:00 2026-06-12T18:29:58+00:00

I am trying to make my program run only while the user enters Y

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I am trying to make my program run only while the user enters Y or y but it only runs once, and even if it isn’t Y or y. Input will either be Y, y, N or n

printf("Welcome to the Jumble Puzzle Solver!\n\n");
printf("Would you like to enter a jumbled word?\n");
scanf("%s", &answer);


    do{

    printf("What word would you like scored?\n");
    scanf("%s", &letters);

    strcpy(changeletters, letters);

    recursivepermute(letters, changeletters, checkword, k, dictionary ,max, min);

    printf("Would you like to enter a jumbled word?\n");
    scanf("%s", &answer);

    }while (answer == 'Y' || answer == 'y');
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  1. Editorial Team
    Editorial Team
    2026-06-12T18:30:00+00:00Added an answer on June 12, 2026 at 6:30 pm

    do { } while() causes the body to always be executed at least once. If you want the condition checked first, just use while:

    // If answer is:
    // char answer;
    
    scanf("%c", &answer);
    while (answer == 'Y' || answer == 'y')
    {
         printf("What word would you like scored?\n");
        // ...
    
        scanf("%c", &answer);
    }
    

    You also need to use scanf("%c" if answer is a char. The %s is to scan a string of characters (ie: char[20]), and would need to be checked differently, using a method like strcmp or similar.

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