Question

I am trying to make some sort of SQL Query where I only get the 10 people with the most referrals, but with minimum 1 referral.

My Table looks like this:

CREATE TABLE IF NOT EXISTS `beta_list` (
  `id` int(10) NOT NULL AUTO_INCREMENT,
  `email` varchar(250) NOT NULL,
  `referrer` int(10) NOT NULL,
  `referral_code` int(10) NOT NULL,
  UNIQUE KEY `id` (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=1;

I have tried something like this:

SELECT 
     email,
     referral_code as refcode,
     (SELECT COUNT(*) FROM beta_list WHERE referrer=refcode) as referrals
  FROM 
     beta_list 
  WHERE
     referrals > 0
  ORDER BY
     referrals DESC
  LIMIT
     10

But it just says “Unknown column ‘referrals’ in ‘where clause'”.

I am no sql guru, I am only just beginning to learn more complex sql queries, so any help on how to achieve something like this would be deeply appreciated!

Cheers!

Answer 1

Try this – Add an outer query to extract the results from inner query –

select ref.email, ref.refcode, ref.referrals from 
(
  SELECT 
     email,
     referral_code as refcode,
     (SELECT COUNT(*) FROM beta_list WHERE referrer=refcode) as referrals
  FROM 
     beta_list
) as ref
WHERE
     ref.referrals > 0
ORDER BY
     ref.referrals DESC
LIMIT
     10