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Asked: May 10, 20262026-05-10T16:28:54+00:00 2026-05-10T16:28:54+00:00

I am trying to match floating-point decimal numbers with a regular expression. There may

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I am trying to match floating-point decimal numbers with a regular expression. There may or may not be a number before the decimal, and the decimal may or may not be present, and if it is present it may or may not have digits after it. (For this application, a leading +/- or a trailing ‘E123’ is not allowed). I have written this regex:

/^([\d]*)(\.([\d]*))?$/ 

Which correctly matches the following:

1 1. 1.23 .23 

However, this also matches empty string or a string of just a decimal point, which I do not want.

Currently I am checking after running the regex that $1 or $3 has length greater than 0. If not, it is not valid. Is there a way I can do this directly in the regex?

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  1. 2026-05-10T16:28:55+00:00Added an answer on May 10, 2026 at 4:28 pm

    I think this will do what you want. It either starts with a digit, in which case the decimal point and digits after it are optional, or it starts with a decimal point, in which case at least one digit is mandatory after it.

    /^\d+(\.\d*)?|\.\d+$/ 
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