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Home/ Questions/Q 7891009
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T06:30:25+00:00 2026-06-03T06:30:25+00:00

I am trying to measure CPU time using following code. timespec time1, time2, temp_time;

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I am trying to measure CPU time using following code.

timespec time1, time2, temp_time;

clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &time1);
 int i;
 int cpu_sum = 0;


 for (i = 0; i < nelements; i++) {

  cpu_sum += array[i];

 }    
clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &time2);
temp_time.tv_sec = time2.tv_sec - time1.tv_sec;
printf( sum: %d using CPU in %lf ms \n",cpu_sum, temp_time.tv_sec);

But I always get time as 0.000ms
Any idea what is wrong here.

Any help would be appreciated.

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-03T06:30:27+00:00Added an answer on June 3, 2026 at 6:30 am
    1. You’re invoking undefined behavior by passing the wrong argument types to printf (time_t, which is probably long, instead of double).

    2. tv_sec just contains the whole seconds part of the time. You need to also use tv_nsec to get the nanoseconds part.

    Try something like:

    temp_time.tv_sec = time2.tv_sec - time1.tv_sec;
    temp_time.tv_nsec = time2.tv_nsec - time2.tv_nsec;
    if (temp_time.tv_nsec < 0) {
        temp_time.tv_nsec += 1000000000;
        temp_time.tv_sec--;
    }
    printf("%lld.%.9ld\n", (long long)temp_time.tv_sec, (long)temp_time.tv_nsec);
    
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