Question

I am trying to open a link on image click using follwoing code

 <img src="AllScripts/SliderImages/images/1Main.png" alt="" title="" onclick="openSliderImage(id);"  onmouseover="this.style.cursor='hand'"  width="800px" height="300px" id="http://www.google.com" />

It is working fine but when generating image using c# write code using response.write code it doesn’t work and goes on the follwoing link

http://localhost:1234/AllScripts/SliderImages/images/1Main.png

Follwoing code is used to write html

 <% {

                               Response.Write(SlidingImages);
                       }

                    %>

I know it pick the image src rather then image id on image click but why?
This is the javascript function

 function openSliderImage(id) {
            alert(id);
            window.open(id, '_blank');
        }

Answer 1

Using ids like that to open links seem like a hack. I would just output the url to like link it has to open as a parameter to the function directly.

<img id="googleImg" onclick="openSliderImage('http://www.google.com');" src="AllScripts/SliderImages/images/1Main.png" alt="" title=""   onmouseover="this.style.cursor='hand'"  width="800px" height="300px" />

Your code doesn’t run cause it will look for a javascript variable by the name ‘id’.