Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 971441
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T02:58:00+00:00 2026-05-16T02:58:00+00:00

I am trying to open a page using urllib2 but i keep getting connection

  • 0

I am trying to open a page using urllib2 but i keep getting connection timed out errors.
The line which i am using is:
f = urllib2.urlopen(url)

exact error is:

URLError: <urlopen error [Errno 110] Connection timed out>

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T02:58:01+00:00Added an answer on May 16, 2026 at 2:58 am

    urllib2 respects robots.txt. Many sites block the default User-Agent.

    Try adding a new User-Agent, by creating Request objects & using them as arguments for urlopen:

    import urllib2
    
    request = urllib2.Request('http://www.example.com/')
    request.add_header('User-agent', 'Mozilla/5.0 (Linux i686)')
    
    response = urllib2.urlopen(request)
    

    Several detailed walk-throughs are available, such as http://www.doughellmann.com/PyMOTW/urllib2/

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm trying to force Safari or IE7 to open a new page using a
im trying to open a file using StreamReader and ive to set a Encoding,
I'm trying to open a file and create a list with each line read
I'm trying to open a Microsoft Excel file in a C# program using the
I'm trying to open and read from a serial port using the System.IO.Ports.SerialPort class.
All of a sudden I start getting this error while trying to open 2
I'm trying to make system of multiple dialogs in one page using jquery dialog...
I'm trying to set up the print page for a document, using PageSetupDialog. Before
I'm trying to upload a file using PHP. My HTML page with the form
I'm trying to get a simpleDialog box to open up via a link using

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.