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Home/ Questions/Q 6210569
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T06:11:00+00:00 2026-05-24T06:11:00+00:00

I am trying to open a web browser with a supplied url, however, after

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I am trying to open a web browser with a supplied url, however, after the last line of the following code, I get a null pointer exception. According to the call stack, Actvity.startActvitity(Intent) is where the exception occurs. This code is in a custom controller class for a sub view of the main activity. Any ideas on how to properly start the web browser via code, ideally from outside the main activity since I would to reuse as much as possible. or at least point me in the right direction.

private void showWebSite() {
            String _url = (String) this.urlview.getText();
            Activity webactivity = new Activity();
            Intent webIntent = new Intent( Intent.ACTION_VIEW );
            webIntent.setData( Uri.parse(_url) );
            webactivity.startActivity( webIntent );
    }
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  1. Editorial Team
    Editorial Team
    2026-05-24T06:11:00+00:00Added an answer on May 24, 2026 at 6:11 am
    private void showWebSite() {
            String _url = (String) this.urlview.getText();
            //Activity webactivity = new Activity(); Not required
            Intent webIntent = new Intent( Intent.ACTION_VIEW );
            webIntent.setData( Uri.parse(_url) );
            this.startActivity( webIntent );
    }
    

    If you want it to be reusable create a static method like this

     public static void showWebSite(Activity activity, String url) {
    
            Intent webIntent = new Intent( Intent.ACTION_VIEW );
            webIntent.setData( Uri.parse(url) );
            activity.startActivity( webIntent );
    }
    
    /* Call from your activities like this */
    
    CLASSNAME.showWebSite(this, (String) this.urlview.getText());
    
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