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Home/ Questions/Q 8973711
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T18:30:39+00:00 2026-06-15T18:30:39+00:00

I am trying to open an interactive ssh shell through fabric. Requirements: Use fabrics

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I am trying to open an interactive ssh shell through fabric.

Requirements:

  • Use fabrics hosts in the connection string to remote
  • Open fully interactive shell in current terminal
  • Works on osx and ubuntu
  • No need for data transfer between fabric/python and remote. So fabric task can end in background.

So far:

fabfile.py:

def test_ssh():
    from subprocess import Popen
    Popen('ssh user@1.2.3.4 -i "bla.pem"', shell=True)

In terminal:

localprompt$ fab test_ssh
localprompt$ tcsetattr: Input/output error

[remote ubuntu welcome here]

remoteprompt$ |

Then if I try to input a command on the remote prompt it is executed locally and I drop back to the local prompt.
Does anyone know a solution?

Note: I am aware of fabrics open_shell, but this does not work for me since the stdout lags behind, rendering this unusable.

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  1. Editorial Team
    Editorial Team
    2026-06-15T18:30:41+00:00Added an answer on June 15, 2026 at 6:30 pm

    A slight modification does the trick:

    def test_ssh():
        from subprocess import call
        call('ssh user@1.2.3.4 -i "bla.pem"', shell=True)
    

    As the answer to this question suggests the error suggests the error comes from the inability of ssh to connect to the stdin/out of a process in the background.

    With call the fabric task does not end in the background, but I am fine with that as long as as it is not interfering with my stdin/out.

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