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Editorial Team
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Asked: 2026-05-27T04:48:44+00:00

I am trying to output an image to a browser and then output HTML

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I am trying to output an image to a browser and then output HTML (not directly related to the image) on the same page. Is this possible? I am having a heck of a time figuring it out. Here is my code I have been messing with:

<?php
    function LoadJpeg($imgname){
        /* Attempt to open */
        $im = @imagecreatefromjpeg($imgname);
        /* See if it failed */
        if(!$im){
            /* Create a black image */
            $im  = imagecreatetruecolor(150, 30);
            $bgc = imagecolorallocate($im, 255, 255, 255);
            $tc  = imagecolorallocate($im, 0, 0, 0);
            imagefilledrectangle($im, 0, 0, 150, 30, $bgc);
            /* Output an error message */
            imagestring($im, 1, 5, 5, 'Error loading ' . $imgname, $tc);
        }
        return $im;
    }

    header('Content-Type: image/jpeg');
    $img = LoadJpeg('images/Ball.jpg');
    imagejpeg($img);
    imagedestroy($img);
    //trying to start my text here
    header('Content-Type text/html; charset=utf-8');
    echo "<br /><h2>ross</h2>";
?>

Right near the bottom of my code is where I try to add in my html. when I run it, I only get the image, then no text after. If I try to move it to the top before the function, right after the opening php tag, the text works correctly, and then I get an error:

Warning: Cannot modify header information – headers already sent by (output started at /Applications/MAMP/htdocs/newimage.php:4) in /Applications/MAMP/htdocs/newimage.php on line 28

Any help would be greatly appreciated, thanks.

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1 Answer

  1. Editorial Team

    Stop and think for a moment. How would you normally embed an image in a HTML file?
    You create two files: text.html and image.jpg. Same here, you will create two scrips, one that outputs the HTML and one that generates the image. The HTML would look like:

    <img src="generateimage.php" alt="generated image"/>
<br/>
<h2>ross</h2>

    The generateimage.php script only generates the image.

    Lets take for example a form that allows the user to create a digital Christmas card: he can select the image and write a personal note beneath it.

    form.html:

    <html><body>
<form action="view_card.php" method="post">
    Select an image:
    <select name="imgname">
        <option value="tree">Picture of Christmas tree</option>
        <option value="santa">Picture of Santa</option>
    </select><br/>

    Write a message:
    <textarea name="message"></textarea>
    <br/>

    <input type="submit" value="View Christmas card"/>
</form>
</body></html>

    view_card.php:

    <html>
  <body>
    Here is your Christmas card:
    <hr/>

    <!-- sending the requested image to the generateimage.php script
         as a GET parameter -->
    <img src="generateimage.php?imgname=<?php echo(urlencode($_POST['imgname'])); ?>"/>
    <?php echo(htmlspecialchars($_POST['message'])); ?>
  </body>
</html>

    generateimage.php:

    <?php
/* Stop evil hackers from accessing files they are not supposed to */
$allowed_files = array('tree' => 'tree.jpg', 'santa' => 'santa.jpg');
if( !isset($allowed_files[$_GET['imgname']])) {
    exit; // Thank you for playing...
}

/* Attempt to open */
$im = @imagecreatefromjpeg($allowed_files[$_GET['imgname']]);

/* See if it failed */
if(!$im){
    /* Create a black image */
    $im  = imagecreatetruecolor(150, 30);
    $bgc = imagecolorallocate($im, 255, 255, 255);
    $tc  = imagecolorallocate($im, 0, 0, 0);
    imagefilledrectangle($im, 0, 0, 150, 30, $bgc);

    /* Output an error message */
    imagestring($im, 1, 5, 5, 'Error loading ' . $imgname, $tc);
}

header('Content-Type: image/jpeg');
imagejpeg($im);
imagedestroy($im);
?>
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