Question

I am trying to overload the << operator, but I get the following error:

error: ambiguous overload for ‘operator<<‘ in ‘std::cout << “Test “‘

..Followed by 5 billion other errors similar to:

c:\mingw\bin../lib/gcc/mingw32/4.5.2/include/c++/ostream:165:7: note:
candidates are: …

This comes up because I’m using cout in my main.cpp file.

Here is my code:

In BinTree.h:

    template <typename T>
    class BinTree{
    ...
    friend std::ostream& operator<< <>(std::ostream&, const T&);

In BinTree.cpp:

    template <typename T>
    std::ostream& operator<< (std:: ostream& o, const T& value){
        return o << value;
    }

Thanks in advance for any help you can give.

Answer 1

Your function has the same signature than the one already defined. This is why the compiler moans about ambigous overload. Your function tries to define a function to stream everything to a ostream. This function already exists in the standards library.

template <typename T>
std::ostream& operator<< (std:: ostream& o, const T& value){
    return o << value;
}

What you perhaps want to do is write a function that defines how a BinTree is streamed (to everything). Please note that the stream type is templated. So if you chain the calls to the stream operator it streams the concrete type.

template <typename T, typename U>
T& operator<< (T& o, const BinTree<U>& value){
    //Stream all the nodes in your tree....
    return o;
}