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Home/ Questions/Q 8456821
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T12:38:50+00:00 2026-06-10T12:38:50+00:00

I am trying to parse a string 26/03/2012 , in dd/mm/yyyy format to Ruby’s

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I am trying to parse a string 26/03/2012, in dd/mm/yyyy format to Ruby’s Date using Date.strptime, as follows:

#!/usr/bin/ruby
require 'date'
puts 'Ruby Version: ' + RUBY_VERSION
date_str = '26/03/2012'

date = Date.strptime(date_str, "%d/%m/%y")
puts 'Parsed Date: ' + date.to_s

The output is:

Ruby Version: 1.8.7
Parsed Date: 2020-03-26

The year part has become 2020, instead of 2012!

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  1. Editorial Team
    Editorial Team
    2026-06-10T12:38:51+00:00Added an answer on June 10, 2026 at 12:38 pm

    That should be %Y upper case, rather than %y:

    date = Date.strptime(date_str, "%d/%m/%Y")
    puts 'Parsed Date: ' + date.to_s
    # Parsed Date: 2012-03-26
    

    From the docs:

     Date (Year, Month, Day):
        %Y - Year with century (can be negative, 4 digits at least)
                -0001, 0000, 1995, 2009, 14292, etc.
        %C - year / 100 (round down.  20 in 2009)
        %y - year % 100 (00..99)
    

    Since %y expects two digits only, it takes the first two 20 and assumes that to be a 2 digit representation of 2020, since 2020 % 100 = 20.

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