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Home/ Questions/Q 9061759
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T15:34:02+00:00 2026-06-16T15:34:02+00:00

I am trying to parse profile name and profile image from Google+ API. I

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I am trying to parse profile name and profile image from Google+ API. I made one script that pulls data for one profile but I need to pull data from multiple account. Here is what I have done so far: http://jsfiddle.net/KTbcX/

I want to insert profile data to each .box class but way I am doing it seems inefficient. What I would like to do is have each each data-id attribute would insert itself into the script. Like so

<div class="box">
  <div class="gplus-data" data-id="113411411661448774142"></div>
</div>
<div class="box">
  <div class="gplus-data" data-id="100300281975626912157"></div>
</div>
<div class="box">
  <div class="gplus-data" data-id="104560124403688998123"></div>
</div>

<script>
$(function() {
    $.getJSON("https://www.googleapis.com/plus/v1/people/ [data-id would go here] ?fields=displayName%2Cimage&key=AIzaSyAQtjGlomf-jLktD8h6je_bHnxYkSDOOyQ", function(data) {
        $('.gplus-data').append('<tbody class="items"></tbody>');
        $('.gplus-data tbody').prepend('<tr><th>Name</th><th>Image</th></tr>');          
            var item = '<td>' + data.displayName + '</td>';
            item += '<td><img src="' +data.image.url + '"></td>';
            $('.items').append('<tr>' + item + '</tr>');
    });
});
</script>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T15:34:03+00:00Added an answer on June 16, 2026 at 3:34 pm

    Try this

    $(function() {
    
        $('.gplus-data').each(function() {
            var that = this;
            $.getJSON("https://www.googleapis.com/plus/v1/people/" + $(this).data('id') + "?fields=displayName%2Cimage&key=AIzaSyAQtjGlomf-jLktD8h6je_bHnxYkSDOOyQ", function(data) {
    
                $(that).append('<tbody class="items"></tbody>');
                $(that).find('tbody').prepend('<tr><th>Name</th><th>Image</th></tr>');
                var item = '<td>' + data.displayName + '</td>';
                item += '<td><img src="' + data.image.url + '"></td>';
                $(that).find('.items').append('<tr>' + item + '</tr>');
    
            });
    
        });
    
    });​
    
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