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Home/ Questions/Q 8671635
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T18:59:47+00:00 2026-06-12T18:59:47+00:00

I am trying to parse this xml (http://www.reddit.com/r/videos/top/.rss) and am having troubles doing so.

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I am trying to parse this xml (http://www.reddit.com/r/videos/top/.rss) and am having troubles doing so. I am trying to save the youtube links in each of the items, but am having trouble because of the “channel” child node. How do I get to this level so I can then iterate through the items?

#reddit parse
reddit_file = urllib2.urlopen('http://www.reddit.com/r/videos/top/.rss')
#convert to string:
reddit_data = reddit_file.read()
#close file because we dont need it anymore:
reddit_file.close()

#entire feed
reddit_root = etree.fromstring(reddit_data)
channel = reddit_root.findall('{http://purl.org/dc/elements/1.1/}channel')
print channel

reddit_feed=[]
for entry in channel:   
    #get description, url, and thumbnail
    desc = #not sure how to get this

    reddit_feed.append([desc])
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  1. Editorial Team
    Editorial Team
    2026-06-12T18:59:48+00:00Added an answer on June 12, 2026 at 6:59 pm

    You can try findall('channel/item')

    import urllib2
    from xml.etree import ElementTree as etree
    #reddit parse
    reddit_file = urllib2.urlopen('http://www.reddit.com/r/videos/top/.rss')
    #convert to string:
    reddit_data = reddit_file.read()
    print reddit_data
    #close file because we dont need it anymore:
    reddit_file.close()
    
    #entire feed
    reddit_root = etree.fromstring(reddit_data)
    item = reddit_root.findall('channel/item')
    print item
    
    reddit_feed=[]
    for entry in item:   
        #get description, url, and thumbnail
        desc = entry.findtext('description')  
        reddit_feed.append([desc])
    
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