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Asked: 2026-05-14T19:44:08+00:00

I am trying to pass a variable (in this case an IP variable of

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I am trying to pass a variable (in this case an IP variable of the user) into a url so when it is displayed on the web it is an automatic link. Below is the code I have and I’m getting an error. Seeking PHP Guru to help a n00b.

$user_tracking_vars = "<br /><br /><strong>Browser and Operating System:</strong> ".$browser."<br /><br /><strong>IP:</strong> <a href=""http://urbangiraffe.com/map/?ip=".$ip."&from=drainhole"">".$ip."</a><br /><br /><strong>Page Visited Before Contact Form:</strong> ".$referred."<br />";
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  1. Editorial Team

    It looks like you’re incorrectly escaping your quotes using Basic-like (href=""..."") syntax. The escape character in PHP is backslash (href=\"...\"). 

    $user_tracking_vars = "<br /><br /><strong>Browser and Operating System:</strong> ".$browser."<br /><br /><strong>IP:</strong> <a href=\"http://urbangiraffe.com/map/?ip=".$ip."&from=drainhole"\>".$ip."</a><br /><br /><strong>Page Visited Before Contact Form:</strong> ".$referred."<br />";

    You can also alternate the quotes used to achieve the same effect (href='...'):

    $user_tracking_vars = "<br /><br /><strong>Browser and Operating System:</strong> ".$browser."<br /><br /><strong>IP:</strong> <a href='http://urbangiraffe.com/map/?ip=".$ip."&from=drainhole'>".$ip."</a><br /><br /><strong>Page Visited Before Contact Form:</strong> ".$referred."<br />";
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