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Home/ Questions/Q 6813139
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:32:07+00:00 2026-05-26T20:32:07+00:00

I am trying to pass parameters to a URL which looks like this: http://www.foobar.com/foo?imageurl=

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I am trying to pass parameters to a URL which looks like this:

http://www.foobar.com/foo?imageurl=

And I want to pass the parameters such as an image URL which is generated itself by another API, and the link for the image turns out as:

http://www.image.com/?username=unknown&password=unknown

However, when I try to use the URL:

http://www.foobar.com/foo?imageurl=http://www.image.com/?username=unknown&password=unknown

It doesn’t work.

I have also tried using encodeURI() and encodeURIComponent() on the imageURL, and that too doesn’t work.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T20:32:07+00:00Added an answer on May 26, 2026 at 8:32 pm

    With PHP

    echo urlencode("http://www.image.com/?username=unknown&password=unknown");
    

    Result

    http%3A%2F%2Fwww.image.com%2F%3Fusername%3Dunknown%26password%3Dunknown
    

    With Javascript:

    var myUrl = "http://www.image.com/?username=unknown&password=unknown";
    var encodedURL= "http://www.foobar.com/foo?imageurl=" + encodeURIComponent(myUrl);
    

    DEMO: http://jsfiddle.net/Lpv53/

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