Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6801889
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T19:09:20+00:00 2026-05-26T19:09:20+00:00

I am trying to perform an ajax call inside a form (a Drupal node

  • 0

I am trying to perform an ajax call inside a form (a Drupal node edit form) , but it seems when performing the call, it submits the form for some reason. Here is a sample code:

jQuery.ajax({
     type: "POST",
     url: "my_custom/url",
     dataType: "html",
     data: {"text": jQuery("#edit-body").html()
      },
     success: function(result){
        console.log(result);
     }
    });  

I can replicate this just by executing it in the console, but I attach this to a button click function inside the form. Any tips on preventing the form from submitting, on a POST ajax call?

Here is the full code as requested

        jQuery("#edit-body").before('<div id="proofread_bot-button-holder"><button type="button"  id="proofread_bot-submit" onclick="return false;">Check with Proofread Bot</button></div>'); 
    jQuery("#proofread_bot-submit").click(function(event){
      event.preventDefault();
      jQuery("#proofread_bot-button-holder").append("<img id=\"proofread_bot_throbber\" src=\"sites/all/modules/proofread_bot/images/throbber.gif\" />");

      jQuery.ajax({
         type: "POST",
         url: "proofread_bot/check",
         dataType: "html",
         data: {"text": jQuery("#edit-' . variable_get('proofread_bot_field') . '").html()
          },
         success: function(proofread_result){
            jQuery("#proofread_bot-submit").after(proofread_result);
            jQuery("#proofread_bot_throbber").remove(); 
         }
        });    
      });
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T19:09:21+00:00Added an answer on May 26, 2026 at 7:09 pm

    You need to override form’s onsubmit event to prevent submitting:

    $("formSelector").bind('submit', function (e) {
        var isValid = someYourFunctionToCheckIfFormIsValid();
        if (isValid) {
            jQuery.ajax({
                type: "POST",
                url: "my_custom/url",
                dataType: "html",
                data: { "text": jQuery("#edit-body").html()
                },
                success: function (result) {
                    console.log(result);
                }
            });
        }
        e.preventDefault();
        return false;
    });
    

    By calling

    e.preventDefault();
    return false;
    

    You prevent synchronous postback from occurring.

    UPDATE:
    If you don’t want to override form submit, maybe you could place your button outside of form tag (you can adjust position with css if necessary)?

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to perform this AJAX post but for some reason I am
I am trying to perform a nested AJAX call using the following code. The
I am trying to perform some unit testing on the iphone but for some
I have a form and I'm trying to perform Ajax posts. With the default
I'm trying to perform an AJAX-request in a view, the user gives some input
I am trying to perform an ajax.get using jquery within document.ready . But the
I'm trying to perform an Ajax query from within a Greasemonkey script, but I'm
My website has been giving me intermittent errors when trying to perform any Ajax
I'm trying to figure out the best way to make an AJAX call to
I am trying to include a Drupal form element in a table I am

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.