Question

I am trying to perform logic based on the values of two integers. Here I am defining my integers, and I also have NSLog so I can see if the values are correct when I run the code:

int theHikeFlag = (int)[theNewHikeFlag objectAtIndex:(theID-1)];
NSLog(@"theHikeFlag: %@",theHikeFlag);
int fromTheDB = [self.detailItem hikeFlag];
NSLog(@"fromTheDB: %d",fromTheDB);

And here is the logic:

if (theHikeFlag==1) {
    hikeString=@"You have";
}
else if (theHikeFlag==0) {
    hikeString=@"You have not";
}
else {
    if (fromTheDB==1) {
        hikeString=@"You have";
    }
    else {
        hikeString=@"You have not";
    }
}

As an example of how this code is working. When theHikeFlag=1 and fromTheDB=0, the code bypasses the if and the else if and goes straight to the else and sets hikeString="You have not". This means that my result is irrelevant of theHikeFlag and is based on the fromTheDB integer.

Answer 1

Since you cannot store ints in an array, the line

(int)[theNewHikeFlag objectAtIndex:(theID-1)];

is not doing what you think it should. You need to pull the data from NSNumber, not cast to int.

int theHikeFlag = [[theNewHikeFlag objectAtIndex:(theID-1)] intValue];

The reason why the log output is correct is a bit funny: you made two mistakes in a row! First, you re-interpreted a pointer as an int, and then you let NSLog re-interpret it as an object again by adding a format specifier %@ that is incompatible with int, but works fine with pointers! Since the int value contains a pointer to NSNumber, NSLog produces the “correct” output.