Question

I am trying to print print this out in the html

 <a id='riverwalk' style='display:none;' href='images/riverwalk/1.jpg' rel='prettyPhoto[riverwalk]'></a>
<a style='display:none;' href='images/riverwalk/2.jpg' rel='prettyPhoto[riverwalk]'></a>
<a style='display:none;' href='images/riverwalk/3.jpg' rel='prettyPhoto[riverwalk]'></a>
<a style='display:none;' href='images/riverwalk/4.jpg' rel='prettyPhoto[riverwalk]'></a>

But i want to do it pro grammatically and this is my code..but just not doing anything at all

$counter = 0;
$directory = "images/riverwalk"
$dir = opendir ("images/riverwalk");
while (false !== ($file = readdir($dir))) {
        if ($counter == 0) {
            echo "<a id='riverwalk' style='display:none;' href='images/riverwalk/$file' rel='prettyPhoto[riverwalk]'></a>";
        $counter++;
        }else{
         echo "<a style='display:none;' href='images/riverwalk/$file' rel='prettyPhoto[riverwalk]'></a>";
    $counter++;
}
}

does anything look off to anyone…i cant view the errors because i cant turn php errors on…any ideas

FIX: the issue was the a semicolon missing on the second line

Answer 1

Take a look at scandir() – it’s much easier to write and debug..

$counter = 0;
$dirf    = 'images/riverwalk';
$dir = scandir($dirf);
foreach($dir as $file) {
   if(($file!='..') && ($file!='.')) {
      if($counter==0)
           echo "<a id='riverwalk' style='display:none;' href='images/riverwalk/$file' rel='prettyPhoto[riverwalk]'></a>";
      else
           echo "<a style='display:none;' href='images/riverwalk/$file' rel='prettyPhoto[riverwalk]'></a>";
      $counter++;
   }
}

If that doesn’t work use is_dir() to check you’re pointing at the correct directory..