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Editorial Team
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Asked: 2026-06-09T17:15:40+00:00

I am trying to print table only if user enters integer value( no string,

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I am trying to print table only if user enters integer value( no string, float etc) but this code is not working let me now what i am missing to get only integer values without using JAVASCRIPT at front end. Let me know if im missing some logic.

This is my php code (index.php) —

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>table Data</title>
</head>

<body>

<table width="29%" border="1">
<form name="mytableform" id="mytableform" action="mytabledata.php" method="POST">
  <tr>
    <td width="42%">Enter any munber :&nbsp;</td>
    <td width="58%"><input type="text" name="mynumber" id="mynumber" />&nbsp;</td>
  </tr>
  <tr>
    <td>Enter limit :&nbsp;</td>
    <td><input name="limit" type="text" id="limit" />&nbsp;</td>
  </tr>
  <tr>
    <td colspan="2"><input type="submit" value="Submit" name="submit" />&nbsp;</td>
    </tr>
 </form> 
</table>

</body>
</html>

My mytabledata.php content file —

<?php

$number = $_POST['mynumber'];
$limit = $_POST['limit'];

//var_dump($number);
//var_dump($limit);

if( is_int($number) )
{
    for($i=1;$i<=$limit;$i++)
    {
    $p= $number * $i;
    echo $number." X ".$i." = "." ".$p.";";
    echo "<br />";
    }
}
else{
echo "Please check the type of data you are entering.";
}
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1 Answer

  1. Editorial Team

    The value from your POST is type of string. To use it you can do this:

    $number = intval( $_POST['mynumber'] );
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