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Home/ Questions/Q 7858183
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T21:18:18+00:00 2026-06-02T21:18:18+00:00

I am trying to print the reverse linked list. But I am getting only

  • 0

I am trying to print the reverse linked list. But I am getting only one value. Where am I going wrong? Please bear with me as I am new to C.

#include<stdio.h>
#include<stdlib.h>

struct itemlist {
    int value;
    struct itemlist *next;
};

typedef struct itemlist item;

int main(void) {
    itemlist *curr,*head,*tail;

    head=NULL;
    tail=NULL;

    for (int i = 1; i < 10; i++) {
        curr=(itemlist *)malloc(sizeof(itemlist));
        curr->value=i;
        curr->next=tail;
        tail=curr;
        if (!head)
            head=curr;
    }

    curr=head;

    while (curr) {
        printf("Curr value is:%d\n",curr->value);
        curr=curr->next;
    }

    return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T21:18:22+00:00Added an answer on June 2, 2026 at 9:18 pm

    This code prints 1 to 9

    #include<stdio.h>
    #include<stdlib.h>
    
    struct itemlist
    {
            int value;
            struct itemlist *next;
    };
    
    typedef struct itemlist item;
    
    int main(void)
    {
            itemlist *curr,*head,*prev;
    
            head=NULL;
            curr=NULL;
            prev=NULL;
    
            for(int i=1;i<10;i++)
            {
                    curr = new itemlist;
                    curr->value = i;
                    curr->next = NULL;
    
                    if (head == NULL)
                       head = curr;
                    if(prev != NULL)
                       prev->next = curr;
    
                    prev = curr;
            }
    
            curr=head;
    
            while(curr)
            {
                    printf("Curr value is:%d\n",curr->value);
                    curr=curr->next;
            }
            return 0;
    }
    
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