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Asked: 2026-05-16T06:18:02+00:00

I am trying to process the following URL via the HttpGet() method: https://graph.facebook.com/search?q=Cafe++Bakery&type=event&access_token=&type=event&access_token=239090718395|lqqOnRWlcJOb3QGp3G4HW2aqhlc .

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I am trying to process the following URL via the HttpGet() method:

https://graph.facebook.com/search?q=Cafe++Bakery&type=event&access_token=&type=event&access_token=239090718395|lqqOnRWlcJOb3QGp3G4HW2aqhlc.

And I get the following exception:

java.lang.IllegalArgumentException: 
Invalid uri 'https://graph.facebook.com/search?q=Cafe++Bakery&type=event&access_token=&type=event&access_token=239090718395|lqqOnRWlcJOb3QGp3G4HW2aqhlc.': Invalid query
    at org.apache.commons.httpclient.HttpMethodBase.<init>(HttpMethodBase.java:222)
    at org.apache.commons.httpclient.methods.GetMethod.<init>(GetMethod.java:89)

Now when I cut & paste that URL into the browswer it works just fine. I am
guess it is some sort of URL Encoding that needs to occur, but I am not sure what I have to change to call url from Http Client.

Thanks in advance.

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1 Answer

  1. Editorial Team

    Use URLEncoder.encode() to encode the URL

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