Question

I am trying to put a 2D array into a database. My code is as follows (this is PHP):

public function addspot($linearray,$data){
    $dbname=$data['dbname'];
    try {
        /* Create a connections with the supplied values */
        $pdo = new PDO("mysql:host=" . Config::read('hostname') . ";dbname=" . Config::read('database'). "", Config::read('username'), Config::read('password'), array(PDO::ATTR_PERSISTENT => true));
    } catch(PDOException $e) {
        /* If any errors echo the out and kill the script */
        return 'Database conncetion fail in assets/garage.class.php!Make sure your database information is correct';
    }

    foreach ($linearray as $lines) {
        $spot="INSERT INTO `$dbname`(`floor`, `spot`, `status`, `uid`, `type`, `time`) VALUES ('$lines[0]', '$lines[1]', '$lines[2]', '$lines[3]', '$lines[4]', CURRENT_TIMESTAMP);";
        $statement = $pdo->prepare($spot);
        if($statement->execute()){
            //silent
        } else {
            return 'Spot not added!';
        }
    }
}

The config values are being read correctly, as well as the statement to add a spot is correct.
I know this because when I run the function it correctly adds 1 “spot” but not the rest of the rows in my 2D array.

My array is as follows:

array (size=16)
0 => 
array (size=5)
  0 => string '1' (length=1)
  1 => string '1' (length=1)
  2 => string '1' (length=1)
  3 => string '0' (length=1)
  4 => string '1' (length=1)
1 => 
array (size=5)
  0 => string '1' (length=1)
  1 => string '2' (length=1)
  2 => string '1' (length=1)
  3 => string '0' (length=1)
  4 => string '1' (length=1)
 (and onwards)

My issue is that the function I have written only writes the first line (line[0]) to the database and the other ones do not get written.

Update
Output (using print_r) of statements:
Placed after the prepare

PDOStatement Object
(
[queryString] => INSERT INTO `Garage2`(`floor`, `spot`, `status`, `uid`, `type`, `time`) VALUES ('1', '1', '1', '0', '1', CURRENT_TIMESTAMP);
)
PDOStatement Object
(
[queryString] => INSERT INTO `Garage2`(`floor`, `spot`, `status`, `uid`, `type`, `time`) VALUES ('1', '2', '1', '0', '1', CURRENT_TIMESTAMP);
)

print_r($pdo->errorInfo()); output
Placed in the else (fail) part of the execute statement

Array
(
[0] => 00000
[1] => 
[2] => 
)

Answer 1

Finally got it.
For those who run into this problem in the future, be sure to check that if you have a primary key on your DB, you are not using the same value twice. My first cell was my primary ID, and thus when the first and second statements both had 1 as the value, it failed.

To find this, I added this right after my prepare()\

$pdo->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING );