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Home/ Questions/Q 8522997
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T07:17:08+00:00 2026-06-11T07:17:08+00:00

I am trying to put dynamic values as an arguments in open_workbook() function of

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I am trying to put dynamic values as an arguments in open_workbook() function of xlrd but it is giving error.
My sample code is:

*******************************************

import xlrd,os
filepath=r’C:\Users\JJ\Desktop\JustForTest\2012_09_10′

for root,dirs,files in os.walk(filepath):

abc=files[0] # To convert List to string, files will be like ['Samplexyx.xls']

wb=xlrd.open_workbook(abc)
sh=wb.sheet_by_index(0)    
for rownum in range(sh.nrows):
    print(sh.row_values(rownum))

*******************************************

In the above code, the value of abc dynamically changes.
When I run above code, it is giving error as: IOError: [Errno 2] No such file or directory: ‘Samplexyx.xls’

I am new to using xlrd and Python. What should I do to dynamically open xls files using xlrd and python?

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  1. Editorial Team
    Editorial Team
    2026-06-11T07:17:10+00:00Added an answer on June 11, 2026 at 7:17 am

    its not looking in the right directory for the file

    xlrd.open_workbook(os.path.join(filepath,abc))
    
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