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Asked: 2026-05-27T07:38:15+00:00

I am trying to quickly solve the following problem: f[r_] := Sum[(((-1)^n (2 r

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I am trying to quickly solve the following problem:

f[r_] := Sum[(((-1)^n (2 r - 2 n - 7)!!)/(2^n n! (r - 2 n - 1)!))
             * x^(r - 2*n - 1), 
         {n, 0, r/2}]; 

Nw := Transpose[Table[f[j], {i, 1}, {j, 5, 200, 1}]]; 

X1 = Integrate[Nw . Transpose[Nw], {x, -1, 1}]

I can get the answer quickly with this code:

$starttime = AbsoluteTime[]; Quiet[LaunchKernels[]]; 
DIM = 50; 
Print["$Version = ", $Version, "  |||  ", 
      "Number of Kernels : ", Length[Kernels[]]]; 

Nw = Transpose[Table[f[j], {i, 1}, {j, 5, DIM, 1}]]; 
nw2 = Nw.Transpose[Nw]; 
Round[First[AbsoluteTiming[nw3 = ParallelMap[Expand, nw2]; ]]] 

intrule = (pol_Plus)?(PolynomialQ[#1, x]&) :> 
      (Select[pol, !FreeQ[#1, x] & ] /. 
         x^(n_.) /; n > -1 :> ((-1)^n + 1)/(n + 1)) + 2*(pol /. x -> 0)]); 

Round[First[AbsoluteTiming[X1 = ParallelTable[row /. intrule, {row, nw3}]; ]]]

X1 
Print["overall time needed in seconds: ", Round[AbsoluteTime[] - $starttime]];

But how can I manage this code if I need to solve the following problem, where a and b are known constants?

       X1 = a Integrate[Nw.Transpose[Nw], {x, -1, 0.235}]
          + b Integrate[Nw.Transpose[Nw], {x,  0.235,1}];
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1 Answer

  1. Editorial Team

    Here’s a simple function to do definite integrals of polynomials

    polyIntegrate[expr_List, {x_, x0_, x1_}] := polyIntegrate[#, {x, x0, x1}]&/@expr
polyIntegrate[expr_, {x_, x0_, x1_}] := Check[Total[# 
  Table[(x1^(1 + n) - x0^(1 + n))/(1 + n), {n, 0, Length[#] - 1}]
  ]&[CoefficientList[expr, x]], $Failed, {General::poly}]

    On its range of applicability, this is about 100 times faster than using Integrate. This should be fast enough for your problem. If not, then it could be parallelized.

    f[r_] := Sum[(((-1)^n*(2*r - 2*n - 7)!!)/(2^n*n!*(r - 2*n - 1)!))*
   x^(r - 2*n - 1), {n, 0, r/2}];
Nw = Transpose[Table[f[j], {i, 1}, {j, 5, 50, 1}]];

a*polyIntegrate[Nw.Transpose[Nw], {x, -1, 0.235}] + 
   b*polyIntegrate[Nw.Transpose[Nw], {x, 0.235, 1}] // Timing // Short

(* Returns: {7.9405,{{0.0097638 a+0.00293462 b,<<44>>,
             -0.0000123978 a+0.0000123978 b},<<44>>,{<<1>>}}} *)
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