Question

I am trying to read a file using BinaryReader. However, I am having trouble in retrieving the value that is expected.

using (BinaryReader b = new BinaryReader(File.Open("file.dat", FileMode.Open)))
{
    int result = b.ReadInt32(); //expected to be 2051
}

"file.dat" is the following …

00 00 08 03 00 00 EA 60

The expected result should be 2051, but it gets something totally irrelevant instead. Note that the result I get everytime is the same.

What is the problem?

Answer 1

BinaryReader.ReadInt32 expects the data to be in Little Endian format. Your data you presented is in Big Endian.

Here’s a sample program that shows the output of how BinaryWriter writes an Int32 to memory:

namespace Endian {
  using System;
  using System.IO;

  static class Program {
    static void Main() {
      int a = 2051;

      using (MemoryStream stream = new MemoryStream()) {
        using (BinaryWriter writer = new BinaryWriter(stream)) {
          writer.Write(a);
        }

        foreach (byte b in stream.ToArray()) {
          Console.Write("{0:X2} ", b);
        }
      }

      Console.WriteLine();
    }
  }
}

Running this produces the output:

03 08 00 00

To convert between the two, you could read four bytes using BinaryReader.ReadBytes(4), reverse the array, and then use BitConverter.ToInt32 to convert it to a usable int.

byte[] data = reader.ReadBytes(4);
Array.Reverse(data);
int result = BitConverter.ToInt32(data);